【每日一题】蓝桥杯历年真题题解 -成绩分析
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梁老师 北京小升初老师～
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1、C/C++
#include<bits/stdc++.h>using namespace std;const int N = 1e4 + 10;int n , sum , a[N];signed main(){cin >> n;for(int i = 1 ; i <= n ; i ++) cin >> a[i] , sum += a[i];cout << *max_element(a + 1 , a + 1 + n) << '\n';cout << *min_element(a + 1 , a + 1 + n) << '\n';cout << setprecision(2) << fixed << 1.0 * sum / n << '\n';return 0;}
2、Java
解法一：
import java.util.*;public class Main {public static void main(String[] args) {Scanner cin = new Scanner(System.in);int n, x;int mi = 100 , ma = 0 , sum = 0; //mi记住当前的最低分，ma记住当前的最高分，sum记住学生得分累计和n = cin.nextInt();for(int i = 1 ; i <= n ; i ++){x = cin.nextInt();if (x < mi) mi = x;if (x > ma) ma = x;sum += x;}System.out.println(ma);System.out.println(mi);System.out.printf("%.2f\n", 1.0 * sum / n); //注意输出格式，保留两位小数cin.close();}}
解法二：
import java.util.*;public class Main {public static void main(String[] args) {Scanner cin = new Scanner(System.in);int n = cin.nextInt();int mi = 101 , ma = 0 , sum = 0;for(int i = 1 ; i <= n ; i ++){int x ;x = cin.nextInt();mi = Math.min(mi , x);ma = Math.max(ma , x);sum += x;}System.out.println(ma);System.out.println(mi);System.out.printf("%.2f\n" , 1.0 * sum / n);cin.close();}}
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